A rod 4.2 m long and 0.50 cm^2 in cross-sectional area is stretched 0.20 cm under a tension of 12,000 Nt. What is the applied stress? What is the resulting strain? What is Young's modulus for this material?
Find Stress and Strain?home theater
Stress = Tension applied divided by area of cross section.
Stress = 12000 / [0.5x10^(-4)] = 2.4 x 10^8 Pa
Strain = elongation / original length = 0.2x10^(-2) / 4.2
= 4.762 x 10^(-4)
Young's modulus = Stress / strain
= [2.4 x 10^8] / [4.762 x 10^(-4)] = 5.04 x 10^13 Pa
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